Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium `M_(1) = 4g` and that of hydrogen `M_(2) = 2g`
The equivalent molar mass of the mixture is
A. `6g`
B. `(13)/(7)g`
C. `(18)/(7)g`
D. None
`("Vol. of He")/("Vol. of" CH_(4)) = (50)/(50) = (1)/(1)`
`("No. of molecules of He")/("No. of molecules of" CH_(4))=(1)/(1)`
`("Mass of He")/("Mass of" CH_(4))=(4)/(16)=(1)/(4)`
`:.` Percentage of `CH_(4)` in mixture `(4)/(5)xx100=80%`
Correct Answer - B
`{:(Fe_(2)S_(3),+,3H_(2)O,+(3)/(2)O_(2),overset(50%)(rarr),2Fe(OH)_(3),+,3S,),(10 " mole ",,20 " mole",,30 " moles",,,,):}`H_(2)O` is the limiting reagent.
moles of `Fe(OH)_(3) = (2)/(3) xx 20 xx 0.5 = (20)/(3)` moles
Correct Answer - b
`pi=(W_(B)xxRxxT)/(M_(B)xxV)`
R, T and V are constants for isotonic solutions
`pi_(x)=pi_(sugar)1/M_(x)=5/342`
`or M_(X)=342/5=68.4`
Mass defect =Mass of nucleons -Mass of nucleus
[here ,A(Mass number )=4
Z(atomic number )=2
`implies `Number of neutrons =2
Number of neutrons =a-Z=4-2=2
Mass of protons +Mass Of 2neutrons...
Molecular formula of acetaldehyde : C2H4O
Moles of acetaldehyde = 2 mol
a. Number of moles of carbon atoms = Moles of acetaldehyde × Number of carbon atoms
= 2 × 2
= 4...
Correct Answer - A
Molar ratio of He and `CH_4=4:1`
`:.` partial pressure `P_(He)=4/5xx20=16` bar
partial pressure `P_(CH_4)=1/5xx20=4`
`:. P_(He):P_(CH_4)=16:4`
`because` time of diffusion is same base
`r_(He)/r_(CH_4)=n_(He)/n_(CH_4)=p_(He)/p_(CH_4)xxsqrt(M_(CH_4)/M_(He))=16/4xxsqrt(16/4)=4xx2=8:1`
Correct Answer - 2
`{:(,A,+,3B,rarr,C+2D,),("Mass",10g,,30g,,,),("Mole",(1)/(2),,1,,,),("Mole S.C.",(1)/(2),,(1)/(3),,,):}`
Produced moles of `D = (2)/(3) xx 1`
`therefore` Produced moles of `F = (5)/(1) xx(2)/(3)xx(60)/(100)=2`