When three fair coins are tossed simultaneously, the probability that at least one head appears is

A) 3/8

B) 1/2

C) 5/8

D) 7/8


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Correct option is: D)\(\frac{7}{8}\)

When three coins are tossed, then possible outcomes are

{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

\(\therefore\) Total possible outcomes = n(s) = 8

Outcomes which favours the event that at least are head appears are 

{TTH, THT, TTH, THH, HTH, HHT, HHH}

\(\therefore\) Total fabourable outcomes = n (E) = 7

\(\therefore\) Probability that at least one head appears is

P = \(\frac {Total \, favourable \, outcome}{Total\, possible \, outcomes}\) = \(\frac 78\)

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Correct option is: D) \(\frac{7}{8}\)

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