When three fair coins are tossed simultaneously, the probability that at least one head appears is
A) 3/8
B) 1/2
C) 5/8
D) 7/8
Correct option is: D)\(\frac{7}{8}\)
When three coins are tossed, then possible outcomes are
{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
\(\therefore\) Total possible outcomes = n(s) = 8
Outcomes which favours the event that at least are head appears are
{TTH, THT, TTH, THH, HTH, HHT, HHH}
\(\therefore\) Total fabourable outcomes = n (E) = 7
\(\therefore\) Probability that at least one head appears is
P = \(\frac {Total \, favourable \, outcome}{Total\, possible \, outcomes}\) = \(\frac 78\)