When two coins tossed simultaneously, the probability of getting at least one head is…… A) 1 B) 1/2 C) 1/4 D) 3/4

Correct Answer - A `P_(1):"4 copper coins 3 silver coins"` `P_(2):"6 copper coins 4 silver coins"` E = Event of copper coin `P(E)=P(P_(1)).P_((E//P_(1)))+P(P_(2)).P(E//P_(2))` `=(10)/(2)xx(4)/(7)+(1)/(2)xx(6)/(10)` `=(41)/(70)`

Correct answer is (b) 1/2

Correct option is: D)\(\frac{7}{8}\) When three coins are tossed, then possible outcomes are {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} \(\therefore\) Total possible outcomes = n(s) = 8 Outcomes which favours the event that at...

Correct option is: D)\(\frac{1}{2^3}\) When 3 coins are tossed, total possible outcomes are {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} \(\therefore\) Total No of possible outcomes when 3 coins are tossed  = 8 = \(2^3\) Fabourable outcome...

Correct option is: A) \(\frac{7}{8}\) When three coins are tossed simultaneously once. Then total possible outcomes are {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} \(\therefore\) Total possible outcomes is n (S) = 8 Favourable outcomes to the...

Correct option is: D) 1 Probability of getting at most two heads = \(\frac {No \,of \,outcomes \,which \,favours \,at \,most \,two\, heads}{Total \,No \,of \,outcomes}\) = \(\frac 44 =1\)