Probability that A speaks truth is `4/5` . A coin is tossed. A reports that a appears. The probability that actually there was head is

Correct option is D) 5

Correct option is: D)\(\frac{7}{8}\) When three coins are tossed, then possible outcomes are {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} \(\therefore\) Total possible outcomes = n(s) = 8 Outcomes which favours the event that at...

Correct option is: B) \(\frac 12\) When a coin is tossed, possible outcomes are {H,T} \(\therefore\) Total outcomes = 2 \(\therefore\) Total favourable outcomes to getting a head = 1 \(\therefore\) Probability of getting a head = \(\frac {Total \,...

The sample space of the experiment is `S = {HHH,HHT,HTH,THH,HT T,THT,T TH,T T T}` `A = {T T T}` `B = {HT T, THT, T TH}` `C = {HHT, HTH,...

Since the trials are independent, so the probability that head appears on the fifth toss does not depend upon previous results of the tosses. Hence, required probability is equal to...

Correct Answer - `4//5` Let `E_(1) and E_(2)` be the events such that `E_(1): ` A speaks truth `E_(2):` A speaks false m Let X be the event that a head appears....

Correct Answer - `n=14` According to question `""^(n)C_(6)((1)/(2))^(6)((1)/(2))^(n-6)=""^(n)C_(8)((1)/(2))^(8)((1)/(2))^(n-8)` `or ""^(n)C_(6)((1)/(2))^(n)=""^(n)C_(8)((1)/(2))^(n)` `or""^(n)C_(6)=""^(n)C_(8)=""^(n)C_(n-8)` `implies6=n-8orn=14`

Correct Answer - B Probability of getting 2 heads in the first 5 trials is `""^(5)C_(2)((1)/(2))^(2)((1)/(2))^(3)=10/32=5/16` Therefore, the probability that third head appears on the sixth trial is `5//16xx1//2=5//32.`

Correct Answer - A The probability of getting a head in a single toss of a coin is P = 1/2 (say). The probability of getting 5 or 6 in a...