The transition of an electron from a 4s orbital to ls orbital in hydrogen atom causes
A. photoelectric effect
B. a Lyman line
C. increase in kinetic energy of electron
D. conversion of `H^+` to H atom
1 Answers
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The electron in hydrogen atom is in the first Bohr orbit `(n = 1)`. The ratio of transition energies, `E(n-1 rarr n =3)` to `E(n=1 rarr n=2)`, is-
Correct Answer - A `DeltaE=13.6 (1/n_(1)^(2)-1/n_(2)^(2))eV//"atom" , (DeltaE_(1 rarr 3))/(DeltaE_(1 rarr 2))=(1/1^(2)-1/3^(2))/(1/1^(2)-1/2^(2))=.32/27`
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Compare the general characteristics of the first transition series of transition metals with those of the second and third transition series metals in
(i) Electronif configuration. There are some exceptions in the electronic configurations. In all the three series. (ii) Oxidation state. The elements belonging to the different series but present in the...
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While filling up electron in the atomic orbitals, 4s orbital is filled before 3d orbital but reverse happens during the ionisation of the atom. Explai
According to (n+1) rule governing the filling of electrons in a multielectron atom, for 4s orbital, n+l=4+0=4 for 3d orbital,m+l=3+2=5. Therefore, 4s orbital fille dbefore electron filling takes place in...
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The radius of the orbit of an electron in a Hydrogen-like atom is `4.5 a_(0)`, where `a_(0)` is the Bohr radius. Its orbital angular momemtum is `(3h)
Correct Answer - A::C Angular momentum `=(nh)/(2pi)=(3h)/(2pi)implies n=3` Also `r=n^(2)/2 a_(0) implies (9a_(0))/2=3^(2)/Z a_(0) implies Z=2` For de-excitation `1/lambda=Rz^(2) [1/n_(1)^(2)-1/n_(2)^(2)]=4R[1/n_(1)^(2)-1/n_(2)^(2)]` For `n=3` to `n=1` : `1/lambda=4R[1/1-1/9] implies lambda=9/(32R)` For `n=3` to...
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The electron in a hydrogen atom makes a transition from `n=n_(1)` to `n=n_(2)` state. The time period of the electron in the initial state `(n_(1))` i
Correct Answer - B In a hydrogen atom the time period is given by `Tpropn^(3)` `(T_(1))/(T_(2))=((n_(1))/(n_(2)))^(3)rArr(8)/(1) ((n_(1))/(n_(3)))^(3)rArr(n_1)/(n_(2))=(2)/(1)` ltbnrgt Thus, the values must be `n_(1)=4 and n_(2)=2`
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The electron in a hydrogen atom makes a transition from M shell to L-shell. The ratio of magnitude of initial to final acceleration of the electron is
Correct Answer - D `a=omega^(2)r` As `" " omegaprop(1)/(n^(3))" " and " : r propn^(2)` `" "aprop(1)/(n^(4))` `rArr" " (a_(M))/(a_(L))=((2)/(3))^(4)=(16)/(81)`
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If `13.6eV` energy is required to separate a hydrogen atom into a proton and an electron, then the orbital radius of electron in a hydrogen atom is
Correct Answer - A Here, `E=-13.6eV=-13.6xx1.6xx10^(-19)=-2.2xx10^(-18)J` `E=(-e^2)/(8piepsilon_0r)` `therefore` As orbital radius, `r=(-e^2)/(8piepsilon_0E)=(9xx10^(9)xx(1.6xx10^(-19))^2)/(2xx(2.2xx10^(-18)))=5.3xx10^(-11)m`.
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An electron collides with a dfixed hydrogen atom in its ground stat. Hydrogen atom gets excited and the collding electron loses all its kinetic energy
Correct Answer - 2 Kinetic energy of electron `= 13.6 [1-1/9] eV = 12.1 eV`.
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The electron in a hydrogen atom makes a transition `n_(1) rarr n_(2)` where `n_(1)` and `n_(2)` are the principal qunatum numbers of the two states. A
Correct Answer - B `T prop n^(3)` `T_(i)/T_(f)=1/27=(n/m)^(3) implies n/m=1/3`
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An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energ
Correct Answer - C Excitation upto `n=3` is required so that visible length is emitted upon de-excitation. So required energy `=13.6 (1-1/9)=12.1 eV`
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