Calculate the amount of work done in rotating a dipole, of dipole moment 5 x 10-8cm, from its position of stable equilibrium to the position of unstable equilibrium, in electric field of intensity 104N/C.
Dipole moment P =5 x10-4Cm.
Electric field (E) =104N/C
At stable equilibrium θ1 = 0°
At unstable equilibrium θ2 =180°
Work done = - PE (cosθ2 - cosθ1)
= -(5 x 10-8 ) (104 ) (cos180 - cos0)
=10 x10-4J
P = 3 x 10-8cm ; E =104N/C
At stable equilibrium (θ1 ) = 0°
At unstable equilibrium (θ2) =180°
Work done in rotating dipole is given by:
W = PE (cosθ1 - cosθ2 )
=...
