Express the change in internal energy of a system when:-
‘w’ amount of work is done by the system and ‘q’ amount of heat is supplied to the system. What type of system would it be?
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The negative of the work done by the conservative internal forces on a system equals the change in
(c) potential energy Explanation:- The Potential energy of a system is due to its configuration. When conservative internal forces do work on the system, the potential energy changes to kinetic energy. So...
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The work done by all the forces (external and internal) on a system equals the change in
(b) kinetic energy Explanation:- Though work done by external forces will change the total energy of the system, work done by the internal forces will increase kinetic energy only. So when both...
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The internal energy of an ideal gas decreases by the same amount as the work done by the system.
The correct answer is (a) (d) (a) The process must be adiabatic. (d) The temperature must decrease.
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Calculate the change in internal energy of a gas kept in a rigid container when 100J of heat is supplied to it.
Q = 100J We know, ΔU = ΔQ – ΔW Here since the container is rigid, ΔV = 0, Hence the ΔW = PΔV = 0, So, ΔU = ΔQ = 100J.
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In a process, 802 J of heat is absorbed by a system and 294 J of work is done by the system. What is the change in internal energy for the process?
ΔU = q + w ΔU = 802 + (-294) =508J
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What happens to the internal energy of the system. if work is done by the system.
ΔU Decreases. (ΔU = q - w)
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What happens to the internal energy of the system. Work is done on the system.
ΔU increases. (ΔU = q + w)
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If a system absorbs 500 cal of heat at the same time does 400J of work, find the change in internal energy of the system.
ΔU = q + w (1 Calorie =4.2 J) ΔU = 2100+(-400) = 1700J
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Express the change in internal energy of a system when:- No heat is absorbed by the system from the surroundings, but work
Δ U = w , wall is adiabatic
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Express the change in internal energy of a system when:- No work is done on the system, but ‘q’ amount of heat is taken out from the system
Δ U = - q, thermally conducting walls
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