The internal energy of an ideal gas decreases by the same amount as the work done by the system.
(a) The process must be adiabatic.
(b) The process must be isothermal.
(c) The process must be isobaric.
(d) The temperature must decrease.
Answered Feb 05, 2023
The correct answer is (a) (d)
According to the first law of thermodynamics, ∆U = q + W (i) Where, ∆U = change in internal energy for a process q = heat W = work Given, q = + 701 J (Since...
Internal energy of the system increases by 307 J.
The correct answer is (c) CA > CB
The correct answer is (d) Q = W
The correct answer is (a) (d) (a) Q = 0. (d) Q≠W.
ΔU = q + w ΔU = 802 + (-294) =508J
ΔU Decreases. (ΔU = q - w)
ΔU increases. (ΔU = q + w)
Δ U = - q, thermally conducting walls
Δ U = q – w, closed system
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