There are 6 multiple choice questions in an examination. How many sequences of answers are possible, if the first three questions have 4 choices each and the next three have 5 choices each?
Given as
Multiple choice question, only one answer is correct of the given options.
For the first three questions only one answer is correct out of four. Therefore it can be answered in 4 ways.
The total number of ways to answer the first 3 questions = 4C1 × 4C1 × 4C1 = 4 × 4 × 4 = 64
Each of the next 3 questions can be answered in 2 ways.
The total number of ways to answer the next 3 questions = 2C1 × 2C1 × 2C1 = 2 × 2 × 2 = 8
Thus, total possible outcomes possible are 64 × 8= 512
Given :
Multiple choice question, only one answer is correct of the given options.
So, for the first three questions only one answer is correct out of four, similarly, for the remaining three question, only one answer is correct out of two.
Number of outcomes possible is 4C1 × 4C1 × 4C1 for the first three and 2C1 × 2C1 × 2C1 for the remaining three.
Hence,
Total possible outcomes possible are 4C1 × 4C1 × 4C1 × 2C1 × 2C1 × 2C1 = 512