In an annual examination Harish scores a total of 421 marks out of 675. What is his approximate percentage in the annual examination ? (a) 56 (b) 72 (c) 92 (d) 88 (e) 62
Answered Feb 05, 2023
(e) Percentage of marks obtained by Harish =421/678 x 100 = 62.4 = 62
(b) Difference = 270 - 216 = 54 According to the question, 8% of total aggregate marks = 54 Total aggregate marks = 54 x 100/8 = 675
(e) According to the question, (40 – 4)% of x = 261 Max marks = 261/36 x 100 = 725
(d) Required % = 555 x 100/850= 65.294% = 65%
(d) Total marks obtained by the student = 6 x 64/100 x 150 = 576 Marks obtained in Hindi and English = 25% of 576 = 576 x 25/100= 14
(b) Required percentage = 1012/1150 x 100 = 88
(e) Required approximate percentage =654 x 100/950% = 68.84% = 69%
(a) Let the maximum marks be x (265+55) = 40x/100 or 320 x 100= 40x x= 320 x 100/40 = 800
(e) Let the maximum marks be x According to the question, 35x /100 +42 =336 x = 840
(d) Marks scored by Mathew = 42 + 51 + 58 + 35 +48 = 234 Max.Marks = 60 × 5 = 300 Percentage scored = 234 /300 x 100 = 78%
By multiplying 48 and 134 we get the answer. 48 x 134= 6432
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