A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is
(a) 196
(b) 280
(c) 346
(d) 140.
Two cases are possible:
(i) Selecting 4 out of first five questions and 6 out of remaining 8 questions
∴ Number of choices in this case = 5C4 × 8C6 = 5C1 × 8C2 = \(\frac{5\times8\times7}{1\times2}=140\)
(ii) Selecting 5 out of first five questions and 5 out of remaining 8 questions.
⇒ Number of choices = 5C5 × 8C5 = 1 × 8C3 = \(\frac{5\times8\times7}{1\times2\times3}=56.\)
∴ Total number of choices = 140 + 56 = 196.