A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is

(a) 196 

(b) 280

(c) 346 

(d) 140.


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Correct option: (a) 196

Explanation:

At least 4 from first 5 questions

Total question = 13 and student has to answer 10 questions

∴ He can choose      (4 from first 5 and 6 from 8) or (5 from first 5 and 5 from 8)

∴ Number of ways  = 5C4 + 8C6 + 5C5 + 8C5 

= (5 × 28) + 56

= 196.

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Two cases are possible: 

(i) Selecting 4 out of first five questions and 6 out of remaining 8 questions 

∴ Number of choices in this case = 5C4 × 8C6 = 5C1 × 8C2 = \(\frac{5\times8\times7}{1\times2}=140\) 

(ii) Selecting 5 out of first five questions and 5 out of remaining 8 questions. 

⇒ Number of choices = 5C5 × 8C5 = 1 × 8C3 = \(\frac{5\times8\times7}{1\times2\times3}=56.\) 

∴ Total number of choices = 140 + 56 = 196.

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