Consider a system of two identical particles. One of the particles is at rest and the other has an acceleration vector a.

Answer is (a) π  \(\vec{A}\times\vec{B}\) = AB sinθ \(\hat{n}\) \(\vec{B}\times\vec{A}\) = AB sin(2π - θ)\(\hat{n}\) AB sinθ \(\hat{n}\) = AB sin(2π - θ)\(\hat{n}\) θ = 2π - θ 2θ = 2π θ = π 

(b) 1/2 vector a. Explanation:  Let the distance of CoM from the origin be X. if each particles with mass m be at distances x1 and x2 then  X= (m*x1+ m*x2)/(m+m)  Velocity of CoM = V...

(a) : vector a = 8vector b vector c = - 7vector b vector a and vector b are parallel and vector b and vector c are antiparallel. Thus vector a and vector c are...

The correct answer is (c) α < β if A > B 

(b) It is possible to have | vector C | < | vector A | and | vector C | < | vector B | 

(c) C must be greater than | A - B|  

(c) A is correct but B is wrong

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A +B=? How?

vector a || vector b ⇒ vector a × vector b = vector 0 ⇒ i(–9 – 3λ) + k(2λ + 6) = vector 0 ⇒ λ = – 3.