Two vector A and vector B are defined as vector A = ai and vector B = a(cosωti + sinωtj), where a is a constant and ω = π/6 rad s-1. If |vector A + vector B| = √3|vector A - vector B| at time t = τ for the first time, the value of τ, in seconds, is _____.
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If vector A x vector B = vector B x vector A ,then the angle between A and B is
Answer is (a) π \(\vec{A}\times\vec{B}\) = AB sinθ \(\hat{n}\) \(\vec{B}\times\vec{A}\) = AB sin(2π - θ)\(\hat{n}\) AB sinθ \(\hat{n}\) = AB sin(2π - θ)\(\hat{n}\) θ = 2π - θ 2θ = 2π θ = π
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A force vector F= vector v x vector A is exerted on a particle in addition to the force of gravity,
Since we need equilibrium, \(v\times A+mg=0\) Given that, \(\vec F=\vec u\times \vec A \) and \(\vec mg\) act on the particle. Velocity must be in direction perpendicular to plane in which gravity acts. Thus, \(v \times A=Av\,sin\theta,\,\theta\) is the angle...
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The non-zero vectors vector a, vector b and vector c are related by vector a = 8vector b and vector c = - 7vector b.
(a) : vector a = 8vector b vector c = - 7vector b vector a and vector b are parallel and vector b and vector c are antiparallel. Thus vector a and vector c are...
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The resultant of vector A and vector B makes an angle a with vector A and β with vector B, (a) α < β
The correct answer is (c) α < β if A > B
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Let vector C = vector A + vector B. (a) | vector C | is always greater than | vector A |
(b) It is possible to have | vector C | < | vector A | and | vector C | < | vector B |
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Let the angle between two nonzero vectors vector A and vector B be 120° and its resultant be vector C.
(c) C must be greater than | A - B|
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The magnitude of the vector product of two vectors vector A and vector B may be (a) greater than AB
(b) equal to AB (c) less than AB (d) equal to zero. Explanation: The magnitude of the vector product of two vectors A and B may be less than or equal to AB, or...
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Consider the following two equations : (A) vector R = 1/M∑imi vector ri and (B) vector a cm = vector F/M.
(c) A is correct but B is wrong
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If vector α=3i-j and vector β=2i+j-3k,then express vector β in the form vector β =vector β1+vector β2,
Thanks mam And big thanks to this app that solves most of the jee question
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If vector a = 2i – j + 3k and vector b = (6i +λj +9k) and vector a || vector b, find the value of λ.
vector a || vector b ⇒ vector a × vector b = vector 0 ⇒ i(–9 – 3λ) + k(2λ + 6) = vector 0 ⇒ λ = – 3.
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