If vector a = 2i – j + 3k and vector b = (6i +λj +9k) and vector a || vector b, find the value of λ.

Answer is (a) π  \(\vec{A}\times\vec{B}\) = AB sinθ \(\hat{n}\) \(\vec{B}\times\vec{A}\) = AB sin(2π - θ)\(\hat{n}\) AB sinθ \(\hat{n}\) = AB sin(2π - θ)\(\hat{n}\) θ = 2π - θ 2θ = 2π θ = π 

Since we need equilibrium, \(v\times A+mg=0\) Given that, \(\vec F=\vec u\times \vec A \) and \(\vec mg\) act on the particle. Velocity must be in direction perpendicular to plane in which gravity acts. Thus, \(v \times A=Av\,sin\theta,\,\theta\) is the angle...

(a) : vector a = 8vector b vector c = - 7vector b vector a and vector b are parallel and vector b and vector c are antiparallel. Thus vector a and vector c are...

The correct answer is (c) α < β if A > B 

(b) It is possible to have | vector C | < | vector A | and | vector C | < | vector B | 

(c) C must be greater than | A - B|  

(b) equal to AB (c) less than AB  (d) equal to zero. Explanation: The magnitude of the vector product of two vectors A and B may be less than or equal to AB, or...

(c) A is correct but B is wrong

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A +B=? How?