A simple pendulum fixed in a car has a time period of 4 seconds when the car is moving uniformly on a horizontal road. When the accelerator is pressed, the time period changes to 3.99 seconds. Making an approximate analysis, find the acceleration of the car.
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A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.
Frequency of oscillations is the number of oscillations of a vibrating object per second. Therefore frequency is = 40 vibrations /4 seconds= 10 Hertz. Time period is the time required to...
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A car accelerates on a horizontal road due to the force exerted by (a) the engine of the car
(d) the road. Explanation: The car pushes the ground in the backward direction and according to the third law of motion, reaction force of the ground in the forward direction acts on...
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A wheel starting from rest is uniformly accelerated at 4 rad/s 2 for 10 seconds.It is allowed to rotate uniformly for the next 10 seconds
Theta=wt+1/2alpha Tsq. By this we will get Theta=200. For first 10 and last 10 sec theta will be same therefore =400. And for 10 sec of middle is alpha ×100= 400. Total =400+400=800rad
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A wheel starting from rest is uniformly accelerated at 4 rad/s 2 for 10 seconds.It is allowed to rotate uniformly for the next 10 seconds
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A simple pendulum fixed in a car has a time period of 4 seconds when the car is moving uniformly on a horizontal road
From where does the 2Π√l/g^2+a• come from ?
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If a simple pendulum has significant amplitude (up to a factor of 1/e of original) only in the period between t = 0 s to t = τ s,
The correct answer is: (c)
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Swapnil, Aakash and Vinay begin to jog around a circular stadium. They complete one lap in 36 seconds, 48 seconds and 42 seconds
(c) They will be together at the starting point after the L.C.M of 36, 48 and 42 L.C.M. of 36, 48, 42 = 1008 seconds
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A car accelerates on a horizontal road due to the force exerted by (a) the engine of the car.
Correct option: (d) the road. Explanation: Car moves on the road due to a reactional force of the road on the car.
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A spring-mass system oacmates hi a car. it the car accelerates on a horizontal road,
(c) remain same EXPLANATION: The frequency of a spring-mass system depends only on the mass and the spring constant, none of which changes in the accelerating car. So the frequency remains the...
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In five minutes distance between a pole and a car changes progressively. What is true about the car ? (A) Car is at rest (B) Car is in motion
(B) Car is in motion
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