An illuminated object is placed on the principal axis of a converging lens so that a real image is formed on the other side of the lens. I

(b) When an object is placed at the centre of curvature in front of a convex lens, its image is formed at the centre of curvature on the other side...

Here, in case of concave mirror u=10 cm [u, is always negative] v =?;m = - 3 [real image] Now the magnification formula is m= -v/u or -3= -(v/-10) or , v = -30 cm. Image will...

For real image of same size, the object must be placed at the distance 2f in front of convex lens, choice (b) is correct.

The image is real, inverted and diminished as the object is placed beyond 2F.

(d) first increases then decreases. EXPLANATION:  The parallel beam of light converges at the focus on the other side and then diverges. Hence till the person moves to the focus the intensity...

(c) the object is real but the image is virtual (d) the object is virtual but the image is real.

(c) the image will not be shifted (d) the intensity of the image will decrease

(a) must be less than 10 cm

(a) remains constant

(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion