A parallel beam of light is incident on a converging lens parallel to its principal axis. As one

(a) Concave mirror as well as convex lens

Given P=+ 1.5D As P=1/f (in metre) , Focal length, f =1/P=1/1.5=0.667m=66.7cm As power of prescribed lens is positive, the lens is converging (or convex) lens.

The SI unit of power of a lens is dioptre. The power of a converging lens is positive as f is +ve.

The correct answer is (c) 2 f EXPLANATION:  The intensity of the light on the other side is maximum where the image of the point source is formed.  Here u = -2f, f...

(d) first increases then decreases. EXPLANATION:  The parallel beam of light converges at the focus on the other side and then diverges. Hence till the person moves to the focus the intensity...

The correct answer is (c) 4 D EXPLANATION:  The plane containing the principal axis will cut the lens in two semicircular pieces and each piece will be a lens having the same...

(c) the image will not be shifted (d) the intensity of the image will decrease

(b) the image will be shifted a little later than the object

Let focal length of converging and diverging lenses be + f and - f respectively. Power of converging len P1 = 1/f, Power of diverging lens P2 = - 1/f ∴ Power of combination P...

λ  = 663 x 10–9 m,  θ= 60°, n = 1 x 1019, λ = h/p => P = p/λ = 10–27 Force exerted on the wall = n(mv cosθ –(–mv cosθ)) = 2n mv cos θ. = 2 x 1 x 1019 x 10–27...