Where should an object be placed in front of a convex lens to get a real image of the size of the object?

(b) – 20 cm is the correct option.

Hint— Draw ray diagrams separately indicating the direction of incident.

Here, in case of concave mirror u=10 cm [u, is always negative] v =?;m = - 3 [real image] Now the magnification formula is m= -v/u or -3= -(v/-10) or , v = -30 cm. Image will...

Given, Distance of image, v = + 50 cm Distanceofobject, u=? Since the image is real, inverted and of the same size of the object, so object should be placed at the...

Radius of curvature of convex mirror, R = 30 cm. Focal length of convex mirror, f=R/2=30cm/2=15cm Now h=5cm,u=-20cm,v=?,h'=? Using the mirror formula 1/f=1/u+1/v, we have 1/v=1/f=1/u=1/15=1/-20=1/15+1/20=(4+3)/60 v=60/7=8.6cm. Thus, image is formed at a distance of 8.6cm...

For real image of same size, the object must be placed at the distance 2f in front of convex lens, choice (b) is correct.

(c) both concave mirror and convex lens.

It is a convex lens. No, when the object is placed close to a convex lens then the image formed is virtual which cannot be obtained on screen.

(c) the image will not be shifted (d) the intensity of the image will decrease

(b) the image will be shifted a little later than the object