The centre of a wheel rolling on a plane surface moves with a speed v0.

Inclination angle (∅)= 30°  Speed of centre of mass (v)= 5m/s  (A) acceleration of the cylinder rolling up the inclined plane is  Given by the formula,  a = -gsin∅/(1 + k²/r²)  Where K = radius...

(ii) 25 km------------------- Solution: Case I: Speed = 40 km/h Time = 15 min = 15/60 hour Distance = Speed × Time = 40×15/60=10 km Case II: Speed = 60 km/h Time = 15 min = 15/60 hour Distance...

(b) : Centripetal force on particle = mRω2  Therefore, F1/F2 = (mR1ω2)/(mR2ω2)= R1/R2.

(a) on the rear wheels is in the forward direction (b) on the front wheels is in the backward direction (c) on the rear wheels has a larger magnitude than the Explanation:  When accelerating the torque...

(c) vA = vB = vc. (d) vB =1/2 (vA+vc).

Thanks dude

 The correct answer is: (a), (c) (a), kinetic  (c) mechanical

The correct answer is all  (a) kinetic  (b) total  (c) mechanical  (d) internal.

(c)  √2v0   Explanation:  Let the radius of the wheel = r.  The angular speed of the wheel ⍵ = v0/r  A particle on the rim of the wheel at the same level as the center...

(a) on the rear wheels is in the forward direction (b) on the front wheels is in the backward direction (c) on the rear wheels has a larger magnitude than the Explanation:  When accelerating the...