The velocity of a particle is v = v0 + gt + ft2 . If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is
(a) v0 + g/2 + f
(b) v0 + 2g + 3f
(c) v0 + g/2 + f/3
(d) v0 + g + f
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A particle is moving in a circular path of radius r. The displacement after half a circle would be:
A particle is moving in a circular path of radius r. The displacement after half a circle would be: (c) 2 r
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Slope of a velocity – time graph gives (a) the distance (b) the displacement (c) the acceleration (d) the speed
(c) the acceleration
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A particle in SHM has time period 8s.How long will it take to travel from mid point to mean position and extreme to extreme point of motion
Since total time period of shm is 8 secs ..which is the time taken to travel from mid position to mean. Time taken to travel from extreme to extreme will be...
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A dimensionless quantity (a) never has a unit, (b) always has a unit, (c) may have a unit, (d) does not exist.
(c) may have a unit, Explanation: Dimensionless quantities may have units.
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A person travelling on a straight line moves with a uniform velocity v_1 for some time and with uniform velocity v_2 for the next equal time.
(a) v = (v1 + v2)/2. Explanation: Let t be the time related to each velocity. Total distance travelled =v1t+v2t. Total time taken=2t. Hence average velocity = v1t+v2t/2t =(v1+v2)/2.
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The position vector of a particle in a circular motion about the origin sweeps out equal area in equal time
(b) speed remains constant (d) tangential acceleration remains constant. Explanation: Velocity and acceleration will not be constant because direction changes continuously. Hence option (a) and (c) are not correct. With a constant speed the position vector will...
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The displacement of a particle in simple harmonic motion in one time period is
The correct answer is (d) zero. EXPLANATION: The displacement is a vector and its magnitude is given by the line joining the initial position to the final position. Since after one time period...
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The displacement of a particle is given by r =A(I cos ω t +j sinωt ).The motion of the particle is
(c) on a circle
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The position vector of a particle in a circular motion about the origin sweeps out equal area in equal time.
(b) speed remains constant (d) tangential acceleration remains constant. Explanation: Velocity and acceleration will not be constant because direction changes continuously. Hence option (a) and (c) are not correct. With a constant speed...
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Assertion (A).Pent-1-ene and pent-2-ene are position isomers Reason (R). Position isomers differ in the position
(a) If both assertion and reason are true, and reason is the true explanation of the assertion.
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