A particle in SHM has time period 8s.How long will it take to travel from mid point to mean position and extreme to extreme point of motion

Let there be two such mid points C and D. Then from above theorem  AC = 1 /2 AB  and AD = 1 /2 AB  ∴ AC = AD  But this is possible only...

Solution: A/√2 from the mean position. where A is amplitude. We know Potential energy = (1/2) kx2 = (1/2) mω 2x2 Kinetic energy = (1/2) mv2 = (1/2) m[ω √ (A2-x2)]2 = (1/2)...

(b) speed remains constant (d) tangential acceleration remains constant. Explanation:  Velocity and acceleration will not be constant because direction changes continuously. Hence option (a) and (c) are not correct. With a constant speed the position vector will...

(b) an extreme position  EXPLANATION:  At the extreme position the particle is in the same phase at consecutive appearance, hence (b) is true. In all other options, the consecutive appearance of the...

The correct answer is (d) zero. EXPLANATION:   The displacement is a vector and its magnitude is given by the line joining the initial position to the final position. Since after one time period...

(c) simple harmonic with amplitude √(A2+B2)

(b) speed remains constant (d) tangential acceleration remains constant. Explanation:  Velocity and acceleration will not be constant because direction changes continuously. Hence option (a) and (c) are not correct. With a constant speed...

(b) an extreme position

(d) All those who travel by air are rich.

(a) If both assertion and reason are true, and reason is the true explanation of the assertion.