The displacement of a particle is given by r =A(I cos ω t +j sinωt ).The motion of the particle is

Solution: cos x + sinx = √ 2 cos x , then (√2 -1 ) cos  x = sin x on multiplying both sides by (√2+1) , we get (√2+1)(√2-1) cos x  = ...

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We have cos(n+1)xcos(n+2)x + sin(n+1)xsin(n+2)x it is from the identity cos(a-b) = cosa * cosb + sina * sinb here a= (n+1)x  and b= (n+2)x so, = cos((n+1)x-(n+2)x) = cos(nx+x-nx-2x) = cos(-x) = cosx { since cos(-x) = cosx...

L.H.S cos6x=cos3(2x) ⇒4cos32x−3cos2x ⇒4(2cos2x−1)3−3(2cos2x−1) ⇒4(8cos6x−12cos4x+6cos2x−1)−6cos2x+3 ⇒32cos6x−48cos4x+24cos2x−4−6cos2x+3 ⇒32cos6x−48cos4x+18cos2x−1=R.H.S Hence proved.

DISPLACEMENT RECATION : in this recation a more active element displaces or removes other element from a compound in solution . FOR EXAMPLE :- Iron + Copper Sulphate gives Iron Sulphate + Copper DOUBLE...

In displacement reaction, more reactive element displaces less reactive element from its compound and in double displacement reaction, two different compounds exchange their ions and form two new compounds. ii. a. Double...

The correct answer is (d) zero. EXPLANATION:   The displacement is a vector and its magnitude is given by the line joining the initial position to the final position. Since after one time period...

(c) simple harmonic with amplitude √(A2+B2)

(b) the velocity but not for the kinetic energy EXPLANATION:  In the principle of superposition for displacement of a particle the net displacement of a particle is the sum of displacements produced...

(c) on a circle