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The angle of elevation of the top of a hill at the foot of the tower is 60 deg and the angle of elevation of the top of the tower from the foot of the hill is 30 deg. If the tower is 50 m high, what is the height of the hill?
A
100 m
B
120 m
C
180 m
D
150 m
Correct Answer:
150 m
The angle of elevation of the top of a tower from a certain point is 30°. If the observed moves 20 m towards the tower, the angle of elevation the angle of elevation of top of the tower increases by 15°. The height of the tower is
A
17.3 m
B
21.9 m
C
27.3 m
D
30 m
The angle of elevation of the top of a tower from a point A on the ground is 30°. On moving a distance of 20 metres towards the foot of the tower to apoint B, the angle of elevation increases to 60°. The height of the tower in meters is
A
\u221a3
B
5\u221a3
C
10\u221a3
D
20\u221a3
The angle of elevation of the top of a 36 m tall tower from the initial position of a person on the ground was 60 deg. She walked away in a manner that the foot of the tower, her initial position and the final position were all in the same straight line. The angle of elevation of the top of the tower from her final position was 30 deg. How much did she walk from her initial position?
A
24\u221a3 m
B
12\u221a3 m
C
24 m
D
36\u221a3 m
Consider a regular hexagon ABCDEF. Two towers are situated at B and C. The angle of elevation from A to the top of the tower at B is 30 deg, and the angle of elevation to the top of the tower at C is 45 deg. What is the ratio of the height of towers at B and C?
A
1:\u221a3
B
1:3
C
1:2
D
1:2\u221a3
From the top of a 20 m high building, the angle of elevation of the top of a tower is 60° and the angle of depression of it's foot is at 45°, then the heightof the tower is (√3=1.732)
A
45.46 m
B
45.64 m
C
54.64 m
D
54.46 m
The angle of elevation of the top of a tower from a certain point is 30°. If the observer moves 40 m towards the tower, the angle of elevation of the top of the tower increases by 15°. The height of the tower is:
A
64.2 m
B
62.2 m
C
52.2 m
D
54.6 m
The angle of elevation of the top of a tower standing on a horizontal plane from a point A is α. After walking a distance 'd' towards the foot of the tower the angle of elevation is found to be β. The height of the tower is
A
$$\frac{d}{{\cot \alpha + \cot \beta }}$$
B
$$\frac{d}{{\cot \alpha - \cot \beta }}$$
C
$$\frac{d}{{\tan \beta - \operatorname{tant} \alpha }}$$
D
$$\frac{d}{{\tan \beta + \operatorname{tant} \alpha }}$$
A tower is broken at a point P above the ground. The top of the tower makes an angle 60° with the ground at Q. From another point R on the opposite sideof Q angle of elevation of point P is 30°. If QR = 180 m, then what is the total height (in metres) of the tower?
A
90
B
45\u221a3
C
45(\u221a3+1)
D
45(\u221a3+2)
On a ground , there is a vertical tower with a flagpole on its top . At a point 9 m away from the foot of the tower , the angles of elevation of the top andbottom of the flagpole are 60° and 30° respectively . The height of the flagpole is
A
5\u221a3 m
B
6\u221a3 m
C
6\u221a2m
D
6\u221a5 m
From the top of a building, the angles of elevation and depression of top and bottom of a tower are 60 deg and 30 deg respectively. If the height of the building is 5m, then the height of the tower is
A
20 m
B
15 m
C
10\u221a3 m
D
5\u221a3 m