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The angle of elevation of the top of a tower from a point A on the ground is 30°. On moving a distance of 20 metres towards the foot of the tower to apoint B, the angle of elevation increases to 60°. The height of the tower in meters is
A
\u221a3
B
5\u221a3
C
10\u221a3
D
20\u221a3
Correct Answer:
10\u221a3
The angle of elevation of the top of a tower from a certain point is 30°. If the observed moves 20 m towards the tower, the angle of elevation the angle of elevation of top of the tower increases by 15°. The height of the tower is
A
17.3 m
B
21.9 m
C
27.3 m
D
30 m
The angle of elevation of the top of a tower from point S is 30°. If the observer moves 10 meters towards the tower which is point T, the angle of elevation of the top increases by 15°. What will be the height of the tower?
A
20 / (√3 – 1) m
B
20√3 m
C
10 / √3 m
D
10 / (√3 – 1) m
The angle of elevation of the top of a tower from a certain point is 30°. If the observer moves 40 m towards the tower, the angle of elevation of the top of the tower increases by 15°. The height of the tower is:
A
64.2 m
B
62.2 m
C
52.2 m
D
54.6 m
A tower is broken at a point P above the ground. The top of the tower makes an angle 60° with the ground at Q. From another point R on the opposite sideof Q angle of elevation of point P is 30°. If QR = 180 m, then what is the total height (in metres) of the tower?
A
90
B
45\u221a3
C
45(\u221a3+1)
D
45(\u221a3+2)
The angle of elevation of the top of a hill at the foot of the tower is 60 deg and the angle of elevation of the top of the tower from the foot of the hill is 30 deg. If the tower is 50 m high, what is the height of the hill?
A
100 m
B
120 m
C
180 m
D
150 m
The angle of elevation of the top of a tower standing on a horizontal plane from a point A is α. After walking a distance 'd' towards the foot of the tower the angle of elevation is found to be β. The height of the tower is
A
$$\frac{d}{{\cot \alpha + \cot \beta }}$$
B
$$\frac{d}{{\cot \alpha - \cot \beta }}$$
C
$$\frac{d}{{\tan \beta - \operatorname{tant} \alpha }}$$
D
$$\frac{d}{{\tan \beta + \operatorname{tant} \alpha }}$$
A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60º. What is the distance between the base of the tower and the point P?
A
Data inadequate
B
8 units
C
12 units
D
None of these
A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60º. What is the distance between the base of the tower and the point P?
A
4 √3 units
B
8 units
C
12 units
D
Data inadequate
E
None of these
A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 45º. What is the distance between the base of the tower and the point P?
A
9 units
B
$$3\sqrt 3 $$ units
C
Data inadequate
D
12 units
The height of a tower is 300 meters. When its top is seen from top of another tower,then the angle of depression is 60°. The horizontal distance between thebases of the two towers is 120 metres. What is the height (in metres) of the small tower?
A
88.24
B
106.71
C
92.15
D
112.64