On a ground , there is a vertical tower with a flagpole on its top . At a point 9 m away from the foot of the tower , the angles of elevation of the top andbottom of the flagpole are 60° and 30° respectively . The height of the flagpole is

A vertical tower stands on ground and is surmounted by a vertical flagpole of height 18 m. At a point on the ground, the angle of elevation of the bottom and the top of the flagpole are 30° and 60° respectively. What is the height of the tower?

A

9 m

B

10.40 m

C

15.57 m

D

12 m

The angle of elevation of the top of a tower from a certain point is 30°. If the observed moves 20 m towards the tower, the angle of elevation the angle of elevation of top of the tower increases by 15°. The height of the tower is

A

17.3 m

B

21.9 m

C

27.3 m

D

30 m

The angle of elevation of the top of a hill at the foot of the tower is 60 deg and the angle of elevation of the top of the tower from the foot of the hill is 30 deg. If the tower is 50 m high, what is the height of the hill?

A

100 m

B

120 m

C

180 m

D

150 m

The angle of elevation of the top of a 36 m tall tower from the initial position of a person on the ground was 60 deg. She walked away in a manner that the foot of the tower, her initial position and the final position were all in the same straight line. The angle of elevation of the top of the tower from her final position was 30 deg. How much did she walk from her initial position?

A

24\u221a3 m

B

12\u221a3 m

C

24 m

D

36\u221a3 m

The angle of elevation of the top of the tower from a point on the ground is $${\sin ^{ - 1}}\left({\frac{3}{5}} \right).$$ If the point of observation is 20 meters away from the foot of the tower, what is the height of the tower?

A

9 m

B

18 m

C

15 m

D

12 m

The angle of elevation of the top of a tower from a point A on the ground is 30°. On moving a distance of 20 metres towards the foot of the tower to apoint B, the angle of elevation increases to 60°. The height of the tower in meters is

A

\u221a3

B

5\u221a3

C

10\u221a3

D

20\u221a3

The angle of elevation of the top of a tower at a point on the ground 50 m away from the foot of the tower is 45°. Then the height of the tower (in metres) is

A

$$50\sqrt 3 $$

B

$$50$$

C

$$\frac{{50}}{{\sqrt 2 }}$$

D

$$\frac{{50}}{{\sqrt 3 }}$$

The angle of elevation of the top of a tower from a certain point is 30°. If the observer moves 40 m towards the tower, the angle of elevation of the top of the tower increases by 15°. The height of the tower is:

A

64.2 m

B

62.2 m

C

52.2 m

D

54.6 m

A tower is broken at a point P above the ground. The top of the tower makes an angle 60° with the ground at Q. From another point R on the opposite sideof Q angle of elevation of point P is 30°. If QR = 180 m, then what is the total height (in metres) of the tower?

A

90

B

45\u221a3

C

45(\u221a3+1)

D

45(\u221a3+2)

The angle of elevation of the top of a tower standing on a horizontal plane from a point A is α. After walking a distance 'd' towards the foot of the tower the angle of elevation is found to be β. The height of the tower is

A

$$\frac{d}{{\cot \alpha + \cot \beta }}$$

B

$$\frac{d}{{\cot \alpha - \cot \beta }}$$

C

$$\frac{d}{{\tan \beta - \operatorname{tant} \alpha }}$$

D

$$\frac{d}{{\tan \beta + \operatorname{tant} \alpha }}$$