What is the enthalpy change of a reaction at 90oC, if the enthalpy of reactant at 90oC and 25oC are 60 J and 25 J, and enthalpy of product at 90oC and 25oC are 80 J and 10 J, and the enthalpy change of reaction at 25oC is 5 J?

Correct Answer: 110 J
Heat of reaction = (60 – 25) + (80 – 10) + 5 = 110 J.