What is the enthalpy change of a reaction at 35oC, if the enthalpy of reactant at 35oC and 25oC are 18 J and 10 J, and enthalpy of product at 35oC and 25oC are 12 J and 8 J, and the enthalpy change of reaction at 25oC is 15 J?

Correct Answer:
Heat of reaction = (18 – 10) + (12 – 8) + 15 = 27 J.