What is the enthalpy change of a reaction at 35oC, if the enthalpy of reactant at 35oC and 25oC are 22 J and 15 J, and enthalpy of product at 35oC and 25oC are 10 J and 5 J, and the enthalpy change of reaction at 25oC is 36 J?

Correct Answer:
Heat of reaction = (22 – 15) + (10 – 5) + 36 = 7 + 5 + 36 = 48 J.