A reactor is supplied with C6H12O6 and the following reactions occur C6H12O6 -> 2C2H5OH + 2CO2 and C6H12O6 –> 2C2H3CO2H + 2H2O, 360 grams of pure glucose is supplied and 44 grams of CO2 was produced, what 90 grams of glucose left unreacted, how many grams of ethanol was produced?

Correct Answer: 46
Moles of glucose reacted in first reaction = 90/180 = 0.5, => weight of ethanol produced = 2*0.5*46 = 46 grams.