A reactor is supplied with C6H12O6 and the following reactions occur C6H12O6 -> 2C2H5OH + 2CO2 and C6H12O6 –> 2C2H3CO2H + 2H2O, 360 grams of pure glucose is supplied and 44 grams of CO2 was produced, what 90 grams of glucose left unreacted, how many grams of propenoic acid was produced?

Correct Answer:
Weight of glucose reacted in first reaction = (44/44)*(1/2)*180 = 90 grams, => (360 – 90 – 90) = 180 grams of glucose reacted in second reaction, => weight of propenoic acid produced = 2*(180/180)*72 = 144 grams.