A reactor is supplied with 5 moles of C4H10, and it undergoes following reactions C4H10 + 4H2O -> 4CO + 9H2 and C4H10 + 6.5O2 -> 4CO2 + 5H2O, if 8 moles of CO2 was produced and 2 moles of C4H10 remains unreacted, what are the number of moles of water produced?

Correct Answer:
Extent of second reaction = (8 – 0)/4 = 2, => moles of water produced = 5*2 = 10.