In an accident a container containing ethanol(s.g 0.789) falls down in a room of dimension 1*1*2(all in m). Ethanol forms a layer of 2mm. Ethanol vaporizes and diffuses through a stagnant film of air of thickness 2.5mm. What will be the time required for the water layer to disappear completely. The diffusivity of ethanol in air is 2.567*10-5 m2/s. the total pressure is 1.013 bar and the pressure of ethanol in bulk air is 0.02244 bar and at the ethanol-air interface is 0.02718bar. The temperature is 25.2°C.

Correct Answer: 4.73h
This is the case of diffusion of through non diffusing B. NA=DP/RTZ*ln⁡ NA=(2.567*10-5*1.013)/(0.08317*298.2*2.5*10-3)*ln⁡ = 2.01*10-6 kmol/m2.s=9.259*10-5kg/m2.s Amount of ethanol = 2*10-3*1=0.002m3=1.578kg Time for evaporation= 1.578/9.259*10-5=17042.87s=4.73h.