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From container A containing 54 liter of mixture of milk and water in ratio of 8 : 1 , 18 liter of the mixture is taken out and poured into container B in which ratio of milk to water is 3 : 1. If difference between total milk and total water in container B is 30 liter then find the quantity of initial mixture in container B.

Correct Answer: 32 Liter\

Let initially milk and water in container B is 3x liter and x liter respectively

Now, 3x + (8/9) × 18 – x – (1/9) × 18 = 30

3x + 16 – x – 2 = 30

x = 8

Initial quantity is container B = 8 (3 + 1) = 32 Liter.

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