Oxygen diffuses through a stagnant layer of air, 1mm thick, ambient temperature 28°C and 1atm total pressure. The partial pressure of oxygen on two sides of layer is P1=0.9atm and P2=0.1atm respectively. Calculate the value of Molar flux (in mol/m2.s) with respect to an observer moving with molar average velocity. Calculate this value at the end of the path where P2=0.1atm. Use R=8.205*10-5m3atmK-1mol-1.

Correct Answer: 1.713
This is a case of diffusion of A through non-diffusing B. Molar flux of oxygen, NA= (DAB*P ln⁡)/RTl Putting all the required values in the above equation. NA=1.904 mol/m2.s Molar average velocity, U= (NA+NB)/C U=NA/C (NB=0) U=NART/P U=4.702*10-2m/s Now, UA=UC/CA UA=U/yA=0.4702 m/s (yA is mole fraction of A at the end) JA=CA(uA-U) =PA*( uA-U)/RT =1.713mol/m2.s.