What amount of ice (in g) will remain when 52 g ice is added to 100 g of water at `40^(@)C`? Specific hate of water is 1 cal//g and latent heat of fusion of ice is `80 cal//g` Round off your answer to next interger.
Answered Feb 05, 2023
Correct Answer - 19
Correct option is: (C) 0.12 Ω
D) Increases then remains constant
Correct Answer - 200
Correct Answer - A `DeltaH=H_(R)-H_(P)`
Correct Answer - C `DeltaS=(DeltaH)/(T)`
Correct Answer - D `beta=(Q_(2))/(W)=(T_(2))/(T_(1)-T_(2))`
Correct Answer - B `C=(R)/(gamma-1)+p(dV)/(dT)` `=(R)/(gamma-1)+alphaV.(R)/(2alphaV)=(R)/(gamma-1)+(R)/(2)=(R(gamma+1))/(2(gamma-1))` `Q=-DeltaU=DeltaU+W , or W=-2DeltaU` `C=(R)/(gamma-1)+((-2RdT)/((gamma-1)dT))=(R)/(1-gamma)` `pdV=(-2RdT)/(gamma-1)` `(RT)/(V)dV=(-2)/(gamma-1)RdT(dT)/(T)=-((gamma-1))/(2)(dV)/(V)` log `T=-((gamma-1))/(2)logV =logV^(-(gamma-1)/(2))+logK` or log `TV^((gamma-1)/(2))=` constant
Correct Answer - `4.16Jcal^(-1)`
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