A potential difference of 20 V is applied across the ends of a coil. The amount of heat generated in it is 800 cal/s. The value of resistance of the coil will be
Given: V = 20 V
d = 1.25 mm = 1.25 × 10-3 m
To Find: Magnitude of electric field (E)
Formula: E = \(\frac{V}{d}\)
Calculation: From formula,
E = \(\frac{20}{1.25\times 10^{-3}}\)
= 1.6 × 104 V/m