Determine two consecutive multiples of 3 whose product is 270.


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Let the consecutive multiples of 3 be a, a + 3 

⇒ a(a + 3) = 270 

⇒ a2 + 3a – 270 = 0 

⇒ a2 + 18a – 15a – 270 = 0 

⇒ a(a + 18) -15(a + 18) = 0 

⇒ (a – 15)(a + 18) = 0 

⇒ a = 15 

Numbers are 15, 18

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