If ‘n’ is even then median is equal to the mean of……………….
A) \(\frac{n}{2}\), \(\frac{n}{2}\)– 1
B) \(\frac{n}{2}\) ,\(\frac{n+1}{2}\)
C) \(\frac{n-1}{2}\), n
D) \(\frac{n}{2}\) , n + 1
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In a statistical data, the difference between mode and mean is k times the difference between median and mean, then what is the value of k?
Correct option is (B) 3 Mode - Mean = k (Median - Mean) Mode = Mean + K.Median - K.Mean Mode = K.Median + (1 - K)Mean We know formula Mode = 3 Median - 2...
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The median of n observations arranged in ascending order when n is even
Correct option is (C) average of and n/2 + n/2 + 1 observations When n is even then median of n observations arranged in ascending order is average of \((\frac{n}{2})^{th}\) and \((\frac{n}{2} + 1)^{th}\)...
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The median of n observations arranged in ascending order when n is even
2 Answers
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Mean of three consecutive even numbers is 16. The numbers are
Correct option is (D) 14, 16, 18 Let three consecutive even numbers are x - 2, x & x+2. \(\therefore\) Their mean \(=\frac{(x-2)+x+(x+2)}3\) \(=\frac{3x}3\) = x But given that mean of three consecutive even numbers is 16. \(\therefore\) x = 16 Thus,...
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While doing a project work on weights of students in the class-room Sekhar found mean of the class as 28 kg, median as 29.5 kg and mode as 27 kg.
C) 27.5, 28.5
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If the mean height of 3 boys is 142 cm. and the mean height of another 7 students is 145 cm., then the mean height of 10 students.
Correct option is (B) 144.1 cm The mean height of 10 boys \(=\frac{3\times142+7\times145}{10}\) \(=\frac{426+1015}{10}\) \(=\frac{1441}{10}\) = 144.1 cm
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If the mean height of 3 boys is 142 cm. and the mean height of another 7 students is 145 cm., then the mean height of 10 students.
2 Answers
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If n is odd, then an + bn is divisible by (a + b) and an− bn is divisible by (a − b). If n is even, then an− bn is divisible by (a − b) and (a + b) .
12011 + 22011 + 32011 +...... +20102011 = (12011 + 20102011) + (22011 + 20092011) + (32011 + 20082011) ...... (10112011 + 10002011) These terms are of the form an + bn, so they will be divided by a + b, as n...
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Use the definition of Odd and Even functions to determine whether each of the following functions is Odd, Even, or neither. Must show your work for credit II! 1) \( f(x)=\frac{x}{1-x^{3}} \) 2) \( f(x)=\frac{x^{2}}{1+x} \) 3) \( \quad f(x)=x-|x| \)
(1) f(x) = \(\frac{x}{1-x^3}\) f(-x) = \(\frac{-x}{1-(-x)^3}\) = \(\frac{-x}{1+x^3}\) ≠ -f(x) or f(x) ∴ f(x) is neither even nor odd function. (2) f(x) = \(\frac{x^2}{1+x}\) ∴ f(-x) = \(\frac{(-x^2)}{1+(-x)}\) = \(\frac{x^2}{1-x}\) ≠ -f(x) or f(x). (3) f(x) = x-|x| ∴ f(-x) = -x-|-x| = -x-|x| = -(x+|x|) ≠ -f(x)...
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The most suitable average for qualitative measurement is (i) Arithmetic mean (ii) Median (iii) Mode (iv) Geometric mean
Correct answer is (ii) Median
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