Vertical axis and horizontal axis are
A) x – axis, y – axis
B) y – axis, x – axis
C) x – axis, x – axis
D) y – axis, y – axis
Given: μS = 0.4, m = 0.25 kg, g = 9.8 m/s2 To find: Force (FL) Formula: FL = μSN = μS(mg) Calculation: From formula, FL = 0.4 × 0.25 × 9.8 = 0.98 N The horizontal force applied...
2 Answers 3 viewsGiven: FL = 120N, Fk = 80N, m = 40 kg, g = 9.8 m/s2 To find: i. Coefficient of static friction (μS) ii. Coefficient of kinetic friction (μk) Formulae: i. μs = \(\frac{F_L}{N}\) ii. μk = \(\frac{F_K}{N}\) Calculation: From formula (i) we get. N =...
2 Answers 1 viewsGiven: m = 20 kg, FL = 100 N, μk = 0.4 To find: i. Coefficient of static friction (μS) ii. Minimum force required (Fk) Formulae: i. μs = \(\frac{F_L}{N}=\frac{F_L}{mg}\) ii. μS = \(\frac{F_K}{N}\) Calculation: From formula (i), μs = \(\frac{100}{20\times9.8}\) = 0.5102 From formula (ii), Fk = μkN...
2 Answers 1 viewsCorrect option is A) 1.5
2 Answers 1 viewsCOLLAR STUD (i) Front view with horizontal axis. (ii) Side view. (iii) Standard dimensions.
2 Answers 1 views(D) may stay in any direction.
2 Answers 1 viewsC) isosceles triangle
2 Answers 1 viewsAnswer is (D) \(\sqrt{5lg}\)
2 Answers 1 viewsCorrect Answer - `1//sqrt(3)`
2 Answers 2 viewsCorrect Answer - 2 `tau=BAIN cos theta`
2 Answers 1 views