The magnetic field of an EM wave travelling along X-axis is vector B = k [4 × 10^-4 sin (ωt – kx)]. Here B is in tesla, t is in second and x is in m.

Monjur Alahi

The magnetic field of an EM wave travelling along X-axis is vector B = k [4 × 10-4 sin (ωt – kx)]. Here B is in tesla, t is in second and x is in m. Calculate the peak value of electric force acting on a particle of charge 5 µC travelling with a velocity of 5 × 105 m/s along the Y-axis.


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Salim Ahmed Kawsar

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Expression for EM wave travelling along X-axis,

\(\overrightarrow{B}\) = \(\hat{k}\) [4 × 10-4 sin (ωt – kx)]

Here, B0 = 4 × 10-4

Given: q = 5 µC = 5 × 10-6 C

v = 5 × 105 m/s along Y-axis

∴ E0 = cB0 = 3 × 108 × 4 × 10-4

= 12 × 104 N/C

Maximum electric force = qE0

= 5 × 10-6 × 12 × 104

= 0.6 N

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