If a certain piece of copper is to be shaped into a conductor of minimum resistance, its length (L) and cross-sectional area A shall be respectively
(A) L/3 and 4 A
(B) L/2 and 2 A
(C) 2L and A2
(D) L and A
Answered Feb 05, 2023
Correct option is: (A) L/3 and 4 A
Correct answer is (D) 16R
Drift velocity and current density will change as it depends upon area of cross-section whereas current will remain constant.
Correct option is: (C) 106 N m-2
(B) \(\frac{F^2 L}{2AY}\) U = \(\frac{1}{2}\) × F × l = \(\frac{1}{2}\) × F × \(\frac{FL}{AY}=\frac{F^2 L}{2AY}\)
Correct option is: (C) both rods will expand equally.
B) increases
Correct option is D) doubled
Correct option is D) halved
Given: R0 = 2.5 Ω α = 4 × 10-3/°C = 0.004/°C T = 80 °C To find: Resistance at 80 °C (RT) Formula: RT = R0(l + αT) Calculation: From formula, RT = 2.5 [1+ (0.004 × 80)] =...
Correct Answer - 9 9
Install the Bissoy app to consult with a doctor.
Log in to ask questions, provide answers, or leave comments.