A force of 1 N doubles the length of a cord having cross-sectional area 1 mm2. The Young’s modulus of the material of cord is
(A) 1 N m-2
(B) 0.5 × 106 N m-2
(C) 106 N m-2
(D) 2 × 106 N m-2
Answered Feb 05, 2023
Correct option is: (C) 106 N m-2
Correct Answer - `1.56 ms^(-1)`
Correct Answer - `3.2xx10^(4)s`
No Young’s modulus Bulk modulus Modulus of rigidity i It is the ratio of longitudinal stress to longitudinal strain. It is the ratio of volume stress to volume strain. It is the ratio of shearing stress to...
Correct Answer - `0.2.5`
Correct option is: (C) 1011 N/m2
Correct option is: (A) 0.42 × 1011 N/m2
(B) \(\frac{F^2 L}{2AY}\) U = \(\frac{1}{2}\) × F × l = \(\frac{1}{2}\) × F × \(\frac{FL}{AY}=\frac{F^2 L}{2AY}\)
Correct option is: (C) both rods will expand equally.
B) increases
D) Force / area
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