The time required to create one inch of top soil
A) 100 – 1000 years
B) 100 – 10,000 years
C) 100 – 5000 years
D) 100 – 15,000 years
Correct Answer - `(20(1+sqrt3))/(sqrt3)m`
2 Answers 1 viewsCorrect Answer - `2 m`
2 Answers 1 views5 years after age of each of father and his two sons will be 10 years more than it was 5years ago. Hence after 5years the sum of thieir age...
2 Answers 1 viewsCorrect Answer - `{:((a)29.41,(b)137.05,(c)0.764,(d)23.206,(e)725.09):}`
2 Answers 1 viewsCorrect option is B) 50000
2 Answers 1 viewsCorrect option is (D) none Let Ramu's present age be x years. \(\therefore\) Ramu's age before 4 years = (x - 4) years Ramu's age after 12 years = (x + 12) years \(\therefore\) x+12 = 3(x-4) \(\Rightarrow\) x+12...
2 Answers 1 views(B) 5 1/2 tons
2 Answers 1 views(1+x) + 2(1+x)2 + 3(1+x)3 + .....+ 1000 (1+x)1000 Now, 1 + (1+x) + (1+x)2 + (1+x)3 + .....+ 1+x)1000 = \(\frac{1-(1+x)^{1001}}{1-(1+x)}\) (∵1+x+x2+......+xn = \(\frac{1-(1+x)^{n+1}}{1-x}\)) By differentiating both sides w.r.t.x, we get ⇒ 1+2(1+x)+3(1+x)2 + .....+1000(1+x)999 = \(\frac{-[x\times -1001(1+x)^{1000}-(1-(1+x)^{1001}\times 1)]}{x^2}\) ⇒ 1+2(1+x)+3(1+x)2 + .....+1000(1+x)999...
2 Answers 1 viewsLet the present age of Shikha be ‘a’ years. Given, product of Shikha’s age five years ago and her age 8 years later is 30 ⇒ (a – 5)(a + 8) =...
2 Answers 1 viewsAlluvial soil.
2 Answers 1 views