A wire of length lm and radius 0.1 mm has a resistance of 100 Ω. The resistivity of the material is ………………….
A) 3.14 × 106 Ω – m
B) 3.14 × 10-6 Ω – m
C) 3.14 Ω – m
D) 3.14 × 108 Ω – m
Answered Feb 05, 2023
We know that R = ρl/A R ∝ l R1/R2 = l1/l2 Given ∵ l2 = 2l1 R1 = 0.60 hm R2/R1 = l2/l1 R2/R1 = 2l1/l1 R2 = 2 R1 R2 = 2 x 0.60 R2 = 1.2 hm
Correct answer is (D) 16R
Answer A) 3 ohm Soln-: 2/x=y/(100-x) 200-2x=xy ......1 After interchanging Y/x+20 = 2/(80-x) 80y-xy=2x+40 .......2 On solving equation 1 and 2 Y=3 ohm
Correct option is: (D) four times that of A.
Correct option is: (B) l
Correct option is: (D) 16
Correct option is A) 400 Ω
Given: R0 = 2.5 Ω α = 4 × 10-3/°C = 0.004/°C T = 80 °C To find: Resistance at 80 °C (RT) Formula: RT = R0(l + αT) Calculation: From formula, RT = 2.5 [1+ (0.004 × 80)] =...
Correct option is: (A) 3.142 m
Correct Answer - 9 9
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