The value of focal length of the eye lens when the object is between infinity and the point of least distance of distinct vision is …………………… 

Correct option is  B) double

Correct option is  A) 25 cm

Correct option is  D) 7 to 8 cm

Correct option is  B) decreases

Correct option is  A) 2.50 cm

Correct option is  C) 2.27 cm

B) hypermetropia

C) beyond the retina

 U = -12 f = -10  1/v - 1/u = 1/f 1/v + 1/12 = 1/10 1/v = 1/60  \(-\frac{1}{v^2} \)dv or \(\frac{1}{u^2} \)du du = \(\frac{v^2}{u^2} \)du \( \frac{v}{u} \)= same path △u1 = △u2 = 1mm △u1 = △v2  △v2 = vf - vi  x2 = △v2 + 1mm x2...