The value of focal length of the eye lens when an object is placed at a distance of least distance of distinct vision is

Correct option is  B) double

Correct option is  A) 25 cm

Correct option is  D) 7 to 8 cm

Correct option is  D) 1 to 2 m

Correct option is  B) decreases

Correct option is  A) 2.50 cm

D) between 2.27 cm to 2.50 cm

C) beyond the retina

 U = -12 f = -10  1/v - 1/u = 1/f 1/v + 1/12 = 1/10 1/v = 1/60  \(-\frac{1}{v^2} \)dv or \(\frac{1}{u^2} \)du du = \(\frac{v^2}{u^2} \)du \( \frac{v}{u} \)= same path △u1 = △u2 = 1mm △u1 = △v2  △v2 = vf - vi  x2 = △v2 + 1mm x2...