Red blood cells: Erythrocytes:: White blood cells: ?
A) Leucocytes
B) Monocytes
C) Thrombocytes
D) Erythrocytes
1 Answers
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There are two boxes, red and white in colour. The ratio of the number of chocolates in the white box to the number of biscuits in the red box is ` 3 :
Correct Answer - ` 18 : 13`
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An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at random. Find the probability that the ball drawn is (i) red (ii) white (iii) red
Correct Answer - `(i) 9/20 (ii) 7/20 (iii) 4/5 (iv) 11/20 (v) 13/20`
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i) All living organisms are composed of cells and products of cells, ii) All cells arise from preexisting cells.
C) Cell theory
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The colour of blood in cockroach A) Red B) White
Correct option is B) White
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Red blood cells are red in colour due to the presence of A) haemoglobin B) fibrinogen
A) haemoglobin
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‘Pus’ is formed by A) Red blood cells B) White blood cells
B) White blood cells
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White blood cells are known as A) Leucocytes B) Erythrocytes
A) Leucocytes
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Number of red blood cells present in 1 ml of blood
Correct option is B) 5 millions
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Match the following. Group – A 1) Erythrocytes 2) Leucocytes
Group – A Group – B 1) Erythrocytes D) RBC 2) Leucocytes A) WBC 3) Scavengers E) Monocytes 4) Microscopic policemen C) Lymphocytes 5) Blood clotting B) Platelets
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A bag contains 1 red and 3 white balls. Find the probability distribution of the number of red balls if 2 balls are drawn at random from the bag
Let X be the random variable defined as the number of red balls. Then X = 0, 1 P(X = 0) = \(\frac{3}{4}\times\frac{2}{3}=\frac{6}{12}=\frac{1}{2}\) P(X = 1) = \(\frac{1}{4}\times\frac{3}{3}+\frac{3}{4}\times\frac{1}{3}=\frac{6}{12}=\frac{1}{2}\) Probability Distribution Table: X 0 1 P(X) \(\frac{1}{2}\) \(\frac{1}{2}\)
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