There are two boxes, red and white in colour. The ratio of the number of chocolates in the white box to the number of biscuits in the red box is ` 3 : 2` and the ratio of the number of biscuits in the white box to the number of chocolates in the red box is ` 3 : 4 `. If the ratio of the total number of chocolates and biscuits in the white box to the total number of chocolates and biscuits in the red box is ` 15 : 16`. Find the ratio of the total number of chocolates to the total number of biscuits in the two boxes.
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Die A has 4 red and 2 white faces, whereas die B has 2 red and 4 white faces. A coins is flipped once. If it shows a head, the game continues by throw
Let R be the event that a red face appears in each of the first n throws. `E_(1):` Die A is used when head has already fallen `E_(2):` Die B...
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There are two urns `Aa n dB` . Urn `A` contains 5 red, 3 blue and 2 white balls, urn `B` contains 4 re3d, 3 blue, and 3 white balls. An urn is chosen
Correct Answer - D Let A nad B, respectively, be the events that urn A and urn B are selected.Let R be the event that the selected ball is red. Since...
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There are 3 bags which are known to contain 2 white and 3 black, 4 white and 1 black, and 3 white and 7 black ball, respectively. A ball is drawn at r
Correct Answer - A Consider the following events. A: ball drawn is black `E_(1):` bag I is chosen `E_(2):` bag II is chosen `E_(3):` bag III is chosen Then, `P(E_(1))=(E_(2))=P(E_(3))=1/3` `P(A//E_(1))=3/5,P(A//E_(2))=1/5,P(A//E_(3))=7/10`...
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A box `B_(1)` contains 1 white ball, 3 red balls, and 2 black balls. An- other box `B_(2)` contains 2 white balls, 3 red balls. A third box `B_(3)` co
Correct Answer - A P (required) = P (all are white) + P (all are red) + P (all are black) `=1/6xx2/9xx3/12+3/6xx3/9xx4/12+2/6xx4/9xx2/12=6/648+36/648+40/648=82/648`
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Let `n_(1)and n_(2)` be the number of red and black balls, respectively, in box I. Let `n_(3) and n_(4)` be the numbers of red and black balls, respec
Correct Answer - A::B `Red ton_(1)` ` "Box" IltBlack ton_(2)` `Red to n_(3)` `"Box II"lt"Black" to n_(4)` `P(R)=1/2.(n_(1))/(n_(1)+n_(2))+1/2.(n_(3))/(n_(3)+n_(4))` `P (II//R) =(1/2(n_(3))/(n_(3)+n_(4)))/(1/2(n_(1))/(n_(1)+n_(2))+1/2.(n_(3))/(n_(3)+n_(4)))` `((n_(3))/(n_(3)+n_(4)))/((n_(1))/(n_(1)+n_(2))+(n_(3))/(n_(3)+n_(4)))` by option `n_(1)=3,n_(2)=3,n_(3)=5,n_(4)=15` `P(II//R)=(5/20)/(3/6+5/20)=(1/4)/(1/2+1/4)=1/4xx(4)/(2+1)=1/3` Also, when `n_(1)=3, n_(2),=6,n_(3)=10, n_(4)=50,P(II//R)=1//3`
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`5` different balls are placed in `5` different boxes randomly. Find the probability that exactly two boxes remain empty. Given each box can hold any
Correct Answer - B `(b)` Each ball can be placed in 5 ways. `:.` Total number of ways, `n(S)=5^(5)` `2` empty boxes, can be selected in `"^(5)C_(2)` ways and `5` balls...
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A box contains `4` white and `3` black balls. Another box contains `3` white and `4` black balls. A die is thrown. If it exhibits a number greater tha
Correct Answer - B `(b)` Let `A` be the event of drawing a black ball. `A_(1)`, the event of choosing the first box. `A_(2)`, the event of choosing the second box....
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Rewrite the given sentences in their order of occurrence. 1. I ate some biscuits and offered some to Hillary.
3. I offered a silent prayer to God in my heart. 5. My daughter Nima gave me a blue pencil, one of her prized possessions, to put at the summit as...
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Arrange the following steps in a sequence to find the area of a leaf. (a) Find the number of complete boxes and half boxes inside the boundary. (b) As
Correct Answer - d,c,e,a,b
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An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at random. Find the probability that the ball drawn is (i) red (ii) white (iii) red
Correct Answer - `(i) 9/20 (ii) 7/20 (iii) 4/5 (iv) 11/20 (v) 13/20`
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