Young’s modulus of material of wire is ‘Y’ and strain energy per unit volume is ‘E’, then the strain is
(A) \(\sqrt{\frac{Y}{2E}}{}\)
(B) \(\sqrt{\frac{E}{Y}}{}\)
(C) \(\sqrt{\frac{2E}{Y}}{}\)
(D) \(\sqrt{2EY}\)
1 Answers
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Strain energy of a stretched wire is 18 × 10^-3 J and strain energy per unit volume of the same wire
Correct answer is (B) 3 m3
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Distinguish between Young’s modulus, bulk modulus and modulus of rigidity.
No Young’s modulus Bulk modulus Modulus of rigidity i It is the ratio of longitudinal stress to longitudinal strain. It is the ratio of volume stress to volume strain. It is the ratio of shearing stress to...
2 Answers 2 views
A steel wire is acted upon by a load of 10 N. Calculate the extension produced in the wire, if the strain energy stored in the wire is 1.1 × 10^-3 J.
Given: F = 10 N, Strain energy = 1.1 × 10-3 J, To find: Extension (l) Formula: W = \(\frac{1}{2}\) × F × l Calculation: From formula, l = \(\frac{2\,W}{F}=\frac{2\times1.1\times10^{-3}}{10}\) = 2.2 × 10-4 m. The extension produced in the wire is...
2 Answers 4 views
Calculate the strain energy per unit volume in a brass wire of length 3 m and area of cross-section 0.6 mm^2 when it is stretched by 3 mm
Given: L = 3 m, F = 6 kg wt = 6 × 9.8N = 58.8N, A = 0.6 mm2 = 0.6 × 10-6 m2, = 3 mm = 3 × 10-3 m To find: Strain energy...
2 Answers 1 views
A force of 100 N produces a change of 0.1% in a length of wire of area of cross section 1 mm^2. Young’s modulus of the wire is ____
Correct option is: (C) 1011 N/m2
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A force of 1 N doubles the length of a cord having cross-sectional area 1 mm^2. The Young’s modulus of the material of cord is
Correct option is: (C) 106 N m-2
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The Young’s modulus of a material is 10^11 Nm^-2 and its Poisson’s ratio is 0.2. The modulus of rigidity of the material is
Correct option is: (A) 0.42 × 1011 N/m2
2 Answers 1 views
Strain energy per unit volume is given by
Correct option is: (A) \(\frac{1}{2}\times\frac{(Stress)^2}{Y}\)
2 Answers 1 views
The strain energy per unit volume of the wire under increasing load is
Correct option is: (C) 0.5 × stress × strain
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If E is an electric field and vector B is the magnetic induction, then the energy flow per unit area per unit time in an electromagnetic
Correct option is: (A) \(\frac{1}{\mu_0}\) \(\overset\rightarrow{E}\times\overset\rightarrow{B}\)
2 Answers 8 views