A cube of aluminium of each side 0.1 m is subjected to a shearing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be
1. The relative displacement of the bottom face and the top face of the cube is called shearing strain.
2. Shearing strain = \(\frac{\triangle\,l}{L}\) = tan θ
where, ∆l = displaced length,
L = Original...
Correct option is (A) 1/6
Possible outcomes are S = {1, 2, 3, 4, 5, 6}
\(\therefore\) n(S) = 6
Number which is a perfect square and a perfect cube is 1. \((\because1^3=1\;\&\;1^2=1)\)
Hence, favourable outcome...